Let’s say you have a directory with hundreds of files with the wrong file names, and you’d like to replace every filename containing test with prod. (this is a contrived example). We can easily do this with the “for” command in bash, combined with a little bit of bash goodness. Today we’ll learn how to replace text in a variable in a for loop.
The “for” command works like this:
for var in;do $var;done
You can replace
This is where the bash variable handling makes it even more interesting. Instead of just doing something like “mv $var”, we can replace text in the filename using this syntax:
${var/originaltext/replacetext}
So now, if we run this command on our directory:
for f in *;do mv $f ${f/test/prod};done
For each file matched by *, bash will execute a command similar to this:
mv test.config prod.config
I’ve found that knowledge of the shell is invaluable when administering servers or just for managing your file collection, and has saved me hours of what would have otherwise been manual work.
And yes, I realize there are a number of tools that can accomplish renaming of multiple files.
I use it frequently for changing filename suffixes.
However, if you are stuck with filenames that contain spaces, you need to quote around the variable and the replacement expression, as shown in the example below.
for f in *;do mv “$f” “${f/\.oga/.ogg}”;done
